Add, remove or ballast with a purpose
Solve the new weighted mean and work backwards from a target CG.
Why does adding aft mass move CG by less than its arm?
The added mass changes the numerator and the denominator.
Use the new total mass
For adding mass w at arm x to an aircraft of mass W at CG X, new CG = (WX + wx)/(W + w). The shift is w(x − X)/(W + w). The lever is measured from the existing CG, not simply from the datum.
For removal, subtract wx and w; the denominator is W − w. Removing mass forward of the existing CG moves the CG aft. The direction is the opposite of adding the same item.
A useful prediction
If the load arm equals the existing CG, adding or removing it changes total mass but not CG. A distant small mass may move CG as much as a nearby larger mass. Always recheck mass limits after a balance correction.
Do not use the fixed-total-mass redistribution formula for addition: its denominator assumes the total mass stays constant.
Predict the direction from the existing CG
The datum arm of an added item can be positive while the item is still forward of the existing CG. For example, an item at 8 m is forward of a CG at 12 m even though both coordinates are positive. Adding it moves CG forward. The relevant direction comes from x minus X, not from the sign of x alone. This remains true with an arbitrary datum ahead of the aircraft.
For a small item relative to total mass, the fixed-mass shift approximation may look close, which makes using it by accident hard to detect. With larger additions the denominator difference becomes material. Derive the new mass and moment explicitly whenever items enter or leave the aircraft. Then compare the answer with the component-arm bounding test and the expected direction before checking the envelope.
How much ballast reaches a target CG?
Rearrange the moment equation before inserting numbers.
Solve the target equation
For added ballast, set target T = (WX + wx)/(W + w). Rearrangement gives w = W(T − X)/(x − T). The denominator uses the distance from ballast station to target CG. Replacing it with x − X gives the fixed-mass approximation and underestimates the addition.
The sign and geometry matter. To move CG aft by adding ballast, its arm must lie aft of the target. If the target is beyond the ballast station, no positive finite addition at that station reaches it.
A balance fix is still a load
Ballast requires approved attachment, location and documentation. A CG correction can consume payload, reduce performance margin and exceed local compartment loads. Recalculate all affected limits.
Removal has a different inverse: removed mass w = W(T − X)/(T − x). The resulting mass must remain positive and the item must exist at the assumed station.
Recognise a poorly placed ballast station
As the ballast station approaches the target CG, the denominator x minus T becomes small and the required added mass becomes very large. This is a geometric limitation, not a calculator malfunction. A station only slightly beyond the target provides little moment leverage relative to the final combined CG. A farther station can achieve the same correction with less added mass, subject to structural and operational approval.
Always substitute the calculated ballast back into the original equation. This independent verification catches an incorrect denominator or a sign reversal. If the solution is negative, interpret it before proceeding: the requested direction may require removal rather than addition, or a different station. A negative answer is not an instruction to create negative cargo. The physical action must match the mathematical operation and the approved loading method.
Can you explain and apply the mechanism?
Four original questions. Work from the stated facts, then compare your reasoning with the explanation.