Hydraulic power, flow and stored energy
Understand hydraulic power, flow and stored energy through causal explanations, a worked case and an interactive laboratory.
Separate pressure, flow, force and speed
Calculate actuator force and speed from pressure, flow and piston area, keeping pressure indication separate from useful movement.
Mechanism and relationships
A hydraulic pump supplies flow. Pressure rises when the flow encounters resistance from a load or restriction. In an ideal static fluid, pressure is transmitted throughout the connected fluid; an actuator converts pressure difference into force, F = Δp × area. Flow determines piston speed through v = Q/area. A larger piston produces more force at the same pressure but moves more slowly at the same flow. Hydraulic power is pressure difference multiplied by volumetric flow.
Reason through the evidence
An indicated normal pressure with little actuator movement can coexist with insufficient flow, a closed valve or a jammed mechanism. A pressure relief valve protects against excessive pressure but does not create useful output when a supply is lost. Check valves enforce a flow direction; filters remove contamination; a reservoir maintains fluid supply and space for thermal and volume changes. Only the approved fluid and servicing standard are compatible with the seals, fire resistance and temperature requirements of that system.
Apply the explanation to a different case
At a fixed 20 MPa pressure, increasing piston area from 20 to 40 cm² raises ideal force from 40 to 80 kN. If the pump still supplies 12 L/min, piston speed falls from 0.10 to 0.05 m/s. Both conclusions must accompany the statement that the larger piston is stronger. A pressure gauge alone cannot show the rate trade-off because it does not measure flow. Restrictions and the actuator return pressure introduce additional losses, which is why the laboratory uses differential pressure rather than assuming that the high-side gauge is the entire effective pressure.
Keep this distinction clear
Entrained air makes a hydraulic system more compressible and can produce spongy or delayed response. The ideal incompressible-fluid equation remains useful for force, but it does not predict that transient compliance. Reservoir pressurisation and return arrangements help the pump receive an appropriate fluid supply.
Read the accumulator and common-source problem
Explain accumulator energy storage and power transfer, then distinguish pressure availability from fluid quantity and source independence.
Mechanism and relationships
A gas-charged accumulator stores energy by compressing gas as hydraulic fluid enters. Gas pressure and volume change together; a simple slow isothermal illustration uses pV = constant with absolute pressure. Precharge determines whether the gas retains an appropriate operating volume. The accumulator smooths pressure fluctuations or provides a specified finite reserve. It is not an inexhaustible replacement for a running pump.
Reason through the evidence
A power transfer unit can transfer mechanical power between hydraulic systems while keeping their fluids separate. This helps only if the supplying side has power and the receiving architecture can use it. A leak may remove fluid even while a pump tries to maintain pressure. Quantity, pressure, temperature and actuator behaviour therefore answer different diagnostic questions. Generic accumulator arithmetic does not establish how many brake applications a particular aeroplane has available.
Apply the explanation to a different case
Imagine a gas accumulator that has an inadequate precharge. It may still show system pressure while connected to a running pump, yet hold the wrong usable fluid volume when the source is removed. Conversely, a charged gas volume without the intended fluid connection cannot power the consumer. Stored pressure, stored volume and the connection path are three separate parts of reserve capability. Gas-law examples must use absolute pressure; inserting a gauge-pressure zero into pV = constant would predict a physically misleading state. The approved service procedure sets the actual precharge and measurement condition.
Keep this distinction clear
A closed isolation valve can preserve one section’s quantity while removing a consumer’s supply. After isolation, apparently improved reservoir behaviour does not itself prove restored consumer availability. A system diagram must show which quantity is protected and which actuator or service has been disconnected.
Can you explain and apply the mechanism?
Four original questions. Work from the stated facts, then compare your reasoning with the explanation.